Brazilian Date Format (DD/MM/YYYY) Regex for Go
/^(0?[1-9]|[12][0-9]|3[01])/(0?[1-9]|1[0-2])/((?:19|20)[0-9]{2})$/What this pattern does
This page provides a well-structured, multi-part regular expression for matching brazilian date format (dd/mm/yyyy), ported and verified for Go. A rigorously tested regex reduces debugging time and protects your application from edge-case failures. The snippet below is ready to drop into your Go project — whether you're validating in a Gin handler, a gRPC service, or a command-line tool.
Go Implementation
// Brazilian Date Format (DD/MM/YYYY)
// ReDoS-safe | RegexVault — Localization > Date Formats
package validation
import "regexp"
var brazilianDateFormatDdmmyyyyRe = regexp.MustCompile(`^(0?[1-9]|[12][0-9]|3[01])/(0?[1-9]|1[0-2])/((?:19|20)[0-9]{2})$`)
func ValidateBrazilianDateFormatDdmmyyyy(s string) bool {
return brazilianDateFormatDdmmyyyyRe.MatchString(s)
}
// Example
// fmt.Println(ValidateBrazilianDateFormatDdmmyyyy("15/01/2024")) // trueTest Cases
Matches (Valid) | Rejects (Invalid) |
|---|---|
15/01/2024 | 00/01/2024 |
1/5/2024 | 32/01/2024 |
31/12/1999 | 15/13/2024 |
01/03/2024 | 2024/01/15 |
| — | 15.01.2024 |
When to use this pattern
This pattern is drawn from the Localization > Date Formats category and carries a ReDoS-safe certification. That matters for Go developers because Go's RE2 engine is inherently safe from catastrophic backtracking, but this pattern has been additionally verified for correctness. RegexVault audits patterns against known backtracking attack vectors, ensuring you have the necessary context before using this regex in a high-stakes production environment.
Common Pitfalls
Brazil spans multiple timezones (UTC-2 to UTC-5). A date on the Brazilian Eastern coast vs Acre state may refer to different calendar days at the same UTC moment.
Technical Notes
Brazil uses DD/MM/YYYY universally. Same regex as UK/European — apply locale context. Portuguese date format occasionally written as 15 de janeiro de 2024 (long form) which requires a different pattern.
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