CVE Identifier Regex for Python
/^CVE-(19[6-9][0-9]|20[0-9]{2})-([0-9]{4,7})$/iWhat this pattern does
This page provides a well-structured, multi-part regular expression for matching cve identifier, ported and verified for Python. In security-sensitive code, using an unverified regex can open the door to both false positives and denial-of-service attacks. The snippet below is ready to drop into your Python project — whether you're validating in a Django view, a FastAPI endpoint, or a standalone data processing script.
Python Implementation
# CVE Identifier
# ReDoS-safe | RegexVault — Security > Network Security
import re
cve_identifier_pattern = re.compile(r'^CVE-(19[6-9][0-9]|20[0-9]{2})-([0-9]{4,7})$')
def validate_cve_identifier(value: str) -> bool:
return bool(cve_identifier_pattern.fullmatch(value))
# Example
print(validate_cve_identifier("CVE-2021-44228")) # TrueTest Cases
Matches (Valid) | Rejects (Invalid) |
|---|---|
CVE-2021-44228 | CVE-2021-123 |
CVE-2024-0001 | CVE-21-44228 |
CVE-2014-0160 | CWE-2021-44228 |
CVE-1999-0001 | CVE-2021-1234ABCD |
CVE-2023-1234567 | — |
When to use this pattern
This pattern is drawn from the Security > Network Security category and carries a ReDoS-safe certification. That matters for Python developers because particularly important in Python web servers where CPU-bound regex operations can stall concurrent request handling. RegexVault audits patterns against known backtracking attack vectors, ensuring you have the necessary context before using this regex in a high-stakes production environment.
Common Pitfalls
NNNNN can be longer than 4 digits for high-volume years (2023 had over 28000 CVEs). Ensure your pattern handles 5-7 digit sequences. CVE IDs with 7 digits appeared starting around 2014.
Technical Notes
CVE format: CVE-YYYY-NNNNN where YYYY is 1960-present year and NNNNN is at least 4 digits. Notable examples: CVE-2021-44228 (Log4Shell), CVE-2014-0160 (Heartbleed), CVE-2017-5638 (Apache Struts/Equifax breach). Year range starts 1960 (earliest MITRE entry).
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