Hebrew Calendar Date Regex for Python
/^(0?[1-9]|[12][0-9]|3[01])/(0?[1-9]|1[0-3])/(5[0-9]{3}|6[0-9]{3})$/What this pattern does
This page provides a well-structured, multi-part regular expression for matching hebrew calendar date, ported and verified for Python. A rigorously tested regex reduces debugging time and protects your application from edge-case failures. The snippet below is ready to drop into your Python project — whether you're validating in a Django view, a FastAPI endpoint, or a standalone data processing script.
Python Implementation
# Hebrew Calendar Date
# ReDoS-safe | RegexVault — Localization > Date Formats
import re
hebrew_calendar_date_pattern = re.compile(r'^(0?[1-9]|[12][0-9]|3[01])/(0?[1-9]|1[0-3])/(5[0-9]{3}|6[0-9]{3})$')
def validate_hebrew_calendar_date(value: str) -> bool:
return bool(hebrew_calendar_date_pattern.fullmatch(value))
# Example
print(validate_hebrew_calendar_date("15/7/5784")) # TrueTest Cases
Matches (Valid) | Rejects (Invalid) |
|---|---|
15/7/5784 | 15/14/5784 |
1/1/5784 | 32/07/5784 |
29/12/5784 | 15/07/2024 |
01/13/5784 | 15/7/4999 |
When to use this pattern
This pattern is drawn from the Localization > Date Formats category and carries a ReDoS-safe certification. That matters for Python developers because particularly important in Python web servers where CPU-bound regex operations can stall concurrent request handling. RegexVault audits patterns against known backtracking attack vectors, ensuring you have the necessary context before using this regex in a high-stakes production environment.
Common Pitfalls
The Hebrew calendar has a 19-year Metonic cycle with 7 leap years. Leap year determination requires the formula (7*year + 1) mod 19 < 7. Regex cannot calculate this — use a library.
Technical Notes
Hebrew calendar has 12 or 13 months (leap years add Adar II, hence month 13). Current year range 5700s-6000s (2024 CE = 5784-5785 AM). Month 13 is only valid in leap years — validate with a Hebrew calendar library.
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