Russian Date Format (DD.MM.YYYY) Regex for JavaScript
/^(0?[1-9]|[12][0-9]|3[01])\.(0?[1-9]|1[0-2])\.((?:19|20)[0-9]{2})$/What this pattern does
This page provides a well-structured, multi-part regular expression for matching russian date format (dd.mm.yyyy), ported and verified for JavaScript. A rigorously tested regex reduces debugging time and protects your application from edge-case failures. The snippet below is ready to drop into your JavaScript project — whether you're validating in an Express middleware, a Next.js API route, or a client-side form.
Javascript Implementation
// Russian Date Format (DD.MM.YYYY)
// ReDoS-safe | RegexVault — Localization > Date Formats
const russianDateFormatDdmmyyyyRegex = /^(0?[1-9]|[12][0-9]|3[01])\.(0?[1-9]|1[0-2])\.((?:19|20)[0-9]{2})$/;
function validateRussianDateFormatDdmmyyyy(input: string): boolean {
return russianDateFormatDdmmyyyyRegex.test(input);
}
// Example
console.log(validateRussianDateFormatDdmmyyyy("15.01.2024")); // trueTest Cases
Matches (Valid) | Rejects (Invalid) |
|---|---|
15.01.2024 | 00.01.2024 |
1.5.2024 | 32.01.2024 |
31.12.1999 | 15.13.2024 |
01.03.2024 | 2024.01.15 |
When to use this pattern
This pattern is drawn from the Localization > Date Formats category and carries a ReDoS-safe certification. That matters for JavaScript developers because especially critical in long-running Node.js event loops where a ReDoS vulnerability can block the entire process. RegexVault audits patterns against known backtracking attack vectors, ensuring you have the necessary context before using this regex in a high-stakes production environment.
Common Pitfalls
Russia uses a Julian-to-Gregorian calendar transition (pre-1918 dates use the Julian calendar, which runs 13 days behind Gregorian in the 20th century). Historical dates require special handling.
Technical Notes
DD.MM.YYYY is the standard format in Russia, Belarus, Ukraine, Kazakhstan, and other post-Soviet states. The dot separator is a reliable locale indicator for this region. Capture groups: 1=day, 2=month, 3=year.
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