UUID Any Version (v1–v8) Regex for Python

What this pattern does

This page provides a well-structured, multi-part regular expression for matching uuid any version (v1–v8), ported and verified for Python. A rigorously tested regex reduces debugging time and protects your application from edge-case failures. The snippet below is ready to drop into your Python project — whether you're validating in a Django view, a FastAPI endpoint, or a standalone data processing script.

Python Implementation

# UUID Any Version (v1–v8)
# ReDoS-safe | RegexVault — Web & Network > Misc

import re

uuid_any_version_v1v8_pattern = re.compile(r'^[0-9a-f]{8}-[0-9a-f]{4}-[1-8][0-9a-f]{3}-[89ab][0-9a-f]{3}-[0-9a-f]{12}$')

def validate_uuid_any_version_v1v8(value: str) -> bool:
    return bool(uuid_any_version_v1v8_pattern.fullmatch(value))

# Example
print(validate_uuid_any_version_v1v8("550e8400-e29b-41d4-a716-446655440000"))  # True

Test Cases

When to use this pattern

This pattern is drawn from the Web & Network > Misc category and carries a ReDoS-safe certification. That matters for Python developers because particularly important in Python web servers where CPU-bound regex operations can stall concurrent request handling. RegexVault audits patterns against known backtracking attack vectors, ensuring you have the necessary context before using this regex in a high-stakes production environment.

Common Pitfalls

Technical Notes

Versions 6, 7, and 8 are defined in RFC 9562 (2024). Version 0 and 9+ are not valid. The nil UUID (all zeros) does not have a valid version number.